Engage NY Eureka Math 4th Grade Module 3 Lesson 34 Answer Key
Eureka Math Grade 4 Module 3 Lesson 34 Problem Set Answer Key
Question 1.
Use the associative property to rewrite each expression.
Solve using disks, and then complete the number sentences.
a. 30 × 24
= ( _3___ × 10) × 24
= __3__ × (10 × 24)
= ___720____
Answer:
30 X 24
= (3 X 10) X 24
= 3 X (10 X 24)
= 720,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 24
= (3 X 10) X 24
= 3 X (10 X 24)
= 720.
b. 40 × 43
= (4 × 10) × __43___
= 4 × (10 × _43__ )
= __1,720_____
Answer:
40 X 43
= (4 X 10) X 43
= 4 X (10 X43)
= 1,720,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 40 X 43
= (4 X 10) X 43
= 4 X (10 X43)
= 1,720.
c. 30 × 37
= (3 × _10___ ) × __37___
= 3 × (10 × __37___ )
= __1,110_____
Answer:
30 × 37
= (3 × 10) × 37
= 3 × (10 × 37)
= 1,110
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 × 37
= (3 × 10) × 37
= 3 × (10 × 37)
= 1,110
Question 2.
Use the associative property and place value disks to solve.
a. 20 × 27
Answer:
20 X 27
= (2 X 10) X 27
= 2 X (10 X 27)
= 540,
Explanation:
Used the associative property and placed value
disks to solve 20 X 27
= (2 X 10) X 27
= 2 X (10 X 27)
= 540 as shown above.
b. 40 × 31
Answer:
40 X 31
= (4 X 10) X 31
= 4 X (10 X 31)
= 1,240,
Explanation:
Used the associative property and placed value
disks to solve 40 X 31
= (4 X 10) X 31
= 4 X (10 X 31)
= 1,240 as shown above.
Question 3.
Use the associative property without place value disks to solve.
a. 40 × 34
Answer:
Explanation:
Used the associative property and placed value
disks to solve 40 X 34
= (4 X 10) X 34
= 4 X (10 X 34)
= 1,360
b. 50 × 43
Answer:
Explanation:
Used the associative property and placed value
disks to solve 50 X 43
= (5 X 10) X 43
= 5 X (10 X 43)
= 2,150
Question 4.
Use the distributive property to solve the following problems.
Distribute the second factor.
a. 40 × 34
Answer:
40 X 34
= (40 X 30 ) + (40 X 4)
= 1,200 + 160
= 1,360,
Explanation:
Used the distributive property and distribute the
second factor as 40 X 34
= (40 X 30 ) + (40 X 4)
= 1,200 + 160
= 1,360.
b. 60 × 25
Answer:
60 X 25
= (60 X 20) + (60 X 5)
= 1,200 + 300
= 1,500,
Explanation:
Used the distributive property and distribute the
second factor as 60 X 25
= (60 X 20) + (60 X 5)
= 1,200 + 300
= 1,500.
Eureka Math Grade 4 Module 3 Lesson 34 Exit Ticket Answer Key
Question 1.
Use the associative property to rewrite each expression.
Solve using disks, and then complete the number sentences.
20 × 41
hundreds tens ones
_(2_ × _10)___ × _41___ = _820_
Answer:
20 X 41
= (2 X 10) X 41
= 2 X (10 X 41)
= 820,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 20 X 41
= (2 X 10) X 41
= 2 X (10 X 41)
= 820.
Question 2.
Distribute 32 as 30 + 2 and solve.
60 × 32
Answer:
= 60 X 32
= 60 X (30 + 2)
= (60 X 30) + (60 X 2)
= 1,800 + 120
= 1,920,
Explanation:
Distributed 32 as 30 + 2 and solved as
= 60 X 32
= 60 X (30 + 2)
= (60 X 30) + (60 X 2)
= 1,800 + 120
= 1,920.
Eureka Math Grade 4 Module 3 Lesson 34 Homework Answer Key
Question 1.
Use the associative property to rewrite each expression.
Solve using disks, and then complete the number sentences.
a. 20 × 34
= (__2__ × 10) × 34
= __2__ × (10 × 34)
= ___680____
Answer:
20 X 34
= (2 X 10) X 34
= 2 X (10 X 34)
= 680,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 20 X 34
= (2 X 10) X 34
= 2 X (10 X 34)
= 680.
b. 30 × 34
= (3 × 10) × __34___
= 3 × (10 × _34__)
= __1,020_____
Answer:
30 X 34
= (2 X 10) X 34
= 3 X (10 X 34)
=1,020
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 34
= (3 X 10) X 34
= 3 X (10 X 34)
= 1,020
c. 30 × 42
= (3 × _10___) × _42____
= 3 × (10 × __42___)
= __1,260_____
Answer:
30 X 42
= (3 X 10) X 42
= 3 X (10 X 42)
= 1,260
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 42
= (3 X 10) X 42
= 3 X (10 X 42)
= 1,260
Question 2.
Use the associative property and place value disks to solve.
a. 20 × 16
Answer:
20 X 16
= (2 X 10) X 16
= 2 X (10 X 16)
= 320,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 20 X 16
= (2 X 10) X 16
= 2 X (10 X 16)
= 320.
b. 40 × 32
Answer:
40 X 32
= (4 X 10) X 32
= 4 X (10 X 32)
= 1,280,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 40 X 32
= (4 X 10) X 32
= 4 X (10 X 32)
= 1,280.
Question 3.
Use the associative property without place value disks to solve.
a. 30 × 21
Answer:
30 X 21
= (3 X 10) X 21
= 3 X (10 X 21)
= 630,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 30 X 21
= (3 X 10) X 21
= 3 X (10 X 21)
= 630.
b. 60 × 42
Answer:
60 X 42
= (6 X 10) X 42
= 6 X (10 X 42)
= 2,520,
Explanation:
Used the associative property to rewrite each expression.
Solved using disks, and then completed the number sentences
as 60 X 42
= (6 X 10) X 42
= 6 X (10 X 42)
= 2,520.
Question 4.
Use the distributive property to solve the following.
Distribute the second factor.
a. 40 × 43
Answer:
40 X 43
= (40 X 40) + (40 X 3)
= 1,600 + 120
= 1,720,
Explanation:
Used the distributive property and distribute the
second factor as 40 X 43
= (40 X 40) + (40 X 3)
= 1,600 + 120
= 1,720.
b. 70 × 23
Answer
= 70 X 23
= (70 X 20) + (70 X 3)
= 1,400 + 210
= 1,610,
Explanation:
Used the distributive property and distribute the
second factor as 60 X 25
= (70 X 20) + (70 X 3)
= 1,400 + 210
= 1,610.
